尔雅控制原理_1期末答案(学习通2023题目答案)
21 min read尔雅控制原理_1期末答案(学习通2023题目答案)
第1单元测验
1、尔雅A open-loop control system utilizes an actuating device to control a process ( ).
A、控制without using feedback
B、原理using feedback
C、期末in engineering design
D、答案in engineering synthesis
2、学习Important modern applications of control systems include which of the following?通题 ( )
A、Safe automobiles
B、目答Autonomous robots
C、尔雅Automated manufacturing
D、控制Biomedical engineering
3、原理The期末 following systems belong to the open-loop control are ( ).
A、washing machine
B、答案water-level automatic control system
C、学习traffic control by means of signal operated on a time basis
D、通题Watt's flyball governor
4、The basic requirements for automatic control systems include ( ).
A、stability
B、rapidity
C、accuracy
D、robust
5、Closed-loop control systems should have which of the following properties: ( )
A、Good regulation against disturbances
B、Desirable responses to commands
C、Low sensitivity to changes in the plant parameters
D、Stable
6、A system is called linear if the principle of superposition applies.
7、In the presence of disturbances, open-loop and closed-loop control system will perform the desired task.
8、A closed-loop control system uses a measurement of the output and feedback of the the signal to compare it with the reference input.
Mathematical Modeling of Control Systems
第2单元测验
1、Consider the system shown in following Figure. If the input is a unit-step input, the final value of the output is ( ).
A、100
B、0.5
C、50
D、5
2、Consider the system shown in following Figure. When all initial conditions are zero, the input is a unit-impulse function, the output c(t) is ( ).
A、
B、
C、
D、
3、Consider a system represented by the block diagram in following Figure. The closed-loop transfer function C(s)/R(s) is ( ).
A、
B、
C、
D、
4、Consider the block diagram in the following Figure. The closed-loop transfer functions C(s)/R(s) and C(s)/N(s) are ( ) respectively.
A、
B、
C、
D、
5、Consider the following differential equation with zero initial conditions and u(t) is a unit-step function. The poles of this system are ( ).
A、-1, -1
B、j1, -j1
C、-1, -2
D、0, -1
6、Use the initial value theorem to find f(0) when
A、3
B、4
C、2
D、1
7、Use the final value theorem to find the final value of f(t) when
A、3
B、4
C、2
D、1
8、Find the transfer function Y(s)/U(s) according to the following differential equation with all initial conditions assumed to be zero.
A、
B、
C、
D、
9、The method to study the nonlinear system is to linearize it. Any nonlinear system should be transformed into a linear system for analysis.
10、The roots of the numerator polynomial of the transfer function are called the zeros of the system.
11、The roots of the characteristic equation are the zeros of the closed-loop system.
12、The transfer function is the ratio of the Laplace transform of the output variable to the Laplace transform of the input variable, with all initial conditions equal to zero.
13、A transfer function may be defined only for a linear, stationary(constant parameter) system.
Transient and Steady-State Response Analyses
第3单元测验
1、Consider a unity negative feedback control system whose open-loop transfer function is The steady-state error to a unit-ramp input is ( ).
A、1
B、0.5
C、1/6
D、
2、Consider a unity negative feedback control system whose open-loop transfer function is The present overshoot of the output to a unit-step input is ( ).
A、9%
B、1%
C、20%
D、no overshoot
3、Consider a unity negative feedback system with the open-loop transfer function Find the value of K so that the damping ratio of the system is 0.707. ( )
A、K=50
B、K=20
C、K=10
D、K=30
4、Consider the unity negative feedback control system with following open-loop transfer function The design specifications are: (1) peak time , and (2) the present overshoot %10%. With K as the design parameter, it follows that ( ).
A、Both specifications can be satisfied.
B、Only the first specification can be satisfied.
C、Only the second specification can be satisfied.
D、Neither specification can be satisfied.
5、Using a 2% criterion, the settling time of following first-order system is ( ) for a unit-step input.
A、1
B、0.8
C、10
D、2
6、If the maximum overshoot of a underdamped second-order system is larger than 5%, then its damping ratio may be ( ).
A、
B、
C、
D、
7、The closed-loop transfer function of a system is The dominant pole(s) for the system is (are) ( ).
A、
B、-60
C、-20
D、-20.3
8、The number of zeros of the forward path transfer function at the origin is called the type number.
9、For a second-order system with no zeros, the percent overshoot to a unit-step input is a function of the damping ratio only.
10、A type-1 system has a zero steady-state tracking error to a ramp input.
11、For the first-order system, the smaller the time constant, the faster the system response.
12、The two second-order systems having the same damping ratio but different undamped natural frequency will exhibit the same overshoot and the same oscillatory pattern.
13、For a desirable transient response of a second-order system, the damping ratio must be larger than 1.
14、Small values of the damping ratio yield excessive overshoot in the transient response, and a system with a large value of damping ratio responds sluggishly.
15、A feedback control system is stable if and only if all closed-loop poles lie in the left-half s plane.
16、When all the coefficients of the characteristic polynomial of a closed-loop system are positive, this closed-loop system is stable.
17、If zero steady-state error for a step input is desired, the type of the system must be one or higher.
18、A unity negative feedback control system with following open-loop transfer function The value of K that yields a steady-state error with a magnitude equal to 0.01 for a unit-step input is ( ).
19、A unity negative feedback system with the following open-loop transfer function The static velocity error constant is ( ).
20、The steady-state error for the type 1 system when it is subjected to the step input is ( ).
21、Consider a first-order system, the input-output relationship is given by The time constant of the first-order system is ( ). Note: the answer is expressed in decimals
The Root Locus Method
第4单元测验
1、The open-loop poles of a negative feedback system on the real axis include -1, -3(double), and the open-loop zero is -2. The root locus of the system on the real axis is ( ).
A、[-2, -1]
B、
C、(-3, -2)
D、
2、Consider a unity-feedback control system with the following open-loop transfer function: The number of separate loci is equal to ( ).
A、1
B、2
C、3
D、4
3、Consider the root locus of a system when the open-loop transfer function is The angles of the asymptotes are ( ).
A、
B、
C、
D、
4、Consider the root locus of a system when the open-loop transfer function is The breakaway point on the real axis is ( ).
A、-2
B、-4
C、0
D、-3
5、On the root locus plot, the number of seperate loci is equal to the number of poles of the open-loop transfer function.
6、The root locus always starts at the zeros and ends at the poles of the open-loop transfer function.
7、The root locus can only be used to stduy the variation of closed-loop poles with the root locus gain.
8、If there is a root locus between an open-loop pole and an open-loop zero point on the real axis, there must be no breakaway and break-in point between them.
9、All the asymptotes of root loci intersect at a point on the real axis.
10、The breakaway points and break-in points correspond to multiple roots of the characteristic equation.
Frequency Response Methods
第5单元测验
1、Consider the stable system represented by the transfer function . When the input r(t)=sin3t, the phase lag for this system is ( ).
A、
B、
C、
D、
2、Consider a feedback control system with the following open-loop transfer function The break frequencies on the open-loop Bode plot are ( ).
A、
B、
C、
D、
3、For a type 1 system, the low-frequency asymptote is a straight-line with a slope of ( ).
A、0dB/dec
B、-20dB/dec
C、-40dB/dec
D、+20dB/dec
4、For a type 0 system, the low-frequency asymptote is a straight-line with a slope of ( ).
A、0dB/dec
B、20dB/dec
C、-20dB/dec
D、-40dB/dec
5、The transfer function G(s) of a system is For the sinusoidal input r(t)=3sin2t, the steady-state output is equal to ( ).
A、
B、
C、
D、
6、The corner frequency (break frequency) of the following first-order factor is ( ).
A、1
B、2
C、0.5
D、4
7、For type 0 system, the starting point of the polar plot is finite and is on the positive real axis.
8、The type of the system determines the slope of the log-magnitude curve at low frequencies.
9、The phase angle of integral factor is constant and equal to .
10、The phase angle of derivative factor is constant and equal to .
11、For a minimum-phase system, both the phase and gain margins must be positive for the system to be stable.
The Design of Feedback Control Systems
第6单元测验
1、The low-frequency region of the open-loop Bode diagram indicates the steady-state behavior of the closed-loop system.
2、If the specifications on phase margin and gain margin are not satisfied, then a suitable compensator that will reshape the open-loop frequency response should be determined.
3、To have a satisfy performance, we should reshape the open-loop frequency-response curve: the gain in the low-frequency region should be large enough, and near the gain crossover frequency, the slope of the log-magnitude curve in the Bode diagram should be -20dB/dec, and the gain should be attenuated rapidly in the high-frequency region.
4、Consider a compensator having the following transfer function This is a phase-lead compensator.
5、Effects of the PD controller are similar to that of phase-lag compensator.
6、A cascade compensator is a compensator that is placed in parallel with the system process.
7、Generally, a phase-lag compensator speeds up the transient response.
8、The arrangement of the system and the selection of suitable components and parameters is part of the process of control system design.
9、A phase-lead compensator can be used to increase the system bandwidth.
10、A compensator is designed for a system with the following transfer function This is phase-lag compensator.
学习通控制原理_1
学习通控制原理_1是一门计算机科学领域的课程，主要介绍了控制理论的基本概念、原理和方法，包括控制系统的模型、控制器的设计、控制系统的性能分析等方面的内容。
控制理论的基本概念
控制是指对一个系统或过程进行干预，使其按照一定的要求或规律运行的过程。控制理论的基本概念包括系统、反馈、控制器等。
系统是指任何由若干个元件组成的整体，可以是物理系统，也可以是信息系统等。反馈是指将系统输出的信息与系统输入的信息进行比较，从而控制系统的运行。控制器是指根据系统的运行状态和要求，对反馈信号进行处理，产生控制信号，控制系统的运行。
控制系统的模型
控制系统的模型是指对控制系统进行建模，将其抽象为一个数学模型，从而方便进行系统分析和控制器设计。控制系统的模型可以是时域模型，也可以是频域模型。
时域模型是指用微分方程或差分方程等描述系统的动态特性。频域模型是指用传递函数描述系统的动态特性，从而方便进行频域分析和控制器设计。
控制器的设计
控制器的设计是指根据系统的模型和性能要求，设计出控制器的结构和参数，使得系统能够按照要求运行。常用的控制器设计方法包括比例-积分-微分控制器(PID控制器)、模糊控制器、神经网络控制器等。
PID控制器是一种常用的控制器，它通过比例、积分、微分三个部分对反馈信号进行加权处理，产生控制信号，控制系统的运行。模糊控制器是一种基于模糊逻辑的控制器，它将系统的输入和输出抽象为模糊量，根据模糊规则产生控制信号，控制系统的运行。神经网络控制器是一种基于神经网络的控制器，通过训练神经网络实现对系统的控制。
控制系统的性能分析
控制系统的性能分析是指对控制系统的性能进行分析，包括稳态性能和动态性能。稳态性能是指在稳态下，系统的输出是否满足要求。动态性能是指系统在受到干扰或变化时，是否能够快速地响应和恢复。
常用的控制系统性能分析方法包括时域分析和频域分析。时域分析是指通过系统的阶跃响应、脉冲响应等分析系统的性能。频域分析是指通过系统的幅频特性、相频特性等分析系统的性能。
总结
学习通控制原理_1是一门非常重要的课程，对于计算机科学领域的学生来说具有重要意义。通过学习本课程，我们可以了解控制理论的基本概念、控制系统的模型、控制器的设计、控制系统的性能分析等方面的知识，为我们今后的学习和研究打下坚实的基础。
琼玉膏使用到了下面哪种调味食材（ ）
A.信用货币是在信用关系发展的基础上产生的，代替金属铸币的货币符号。
B.在练习太极拳中的过程，一旦出现膝盖疼的现象，就说明习练者不适合练习太极拳。
C.概念“主食”和“米饭”是什么关系
D.蓝氏贾第鞭毛虫病的主要临床表现是
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A.从信息处理的视角看，MIS有哪些基本功能
B.根据其中的两视图，选出正确的立体示意图为 ( )。 A B C D
C.大学生的人际交往由单一性向复杂性发展。
D.目前广泛使用的对称秘钥加密标准叫做
下列哪种材料适合作为机床床身材料
A.浏览器与Web服务器之间通信采用的协议为( )
B.检索系统的处理方式描述不正确的是
C.由质子理论对酸碱的定义可知，(NH4)2CO3只是一种碱。 （）
D.标示基准线的起始点尽量设在人体模型的右侧。
（ ）产生的气流是语言发音的原动力
A.一般来说，体积小的照相机更适合“扫街”。
B.在V-M系统中，当晶闸管
C.（ ）印度人的交换行为不是一种等意义交换。
D.DNA的一级结构是双螺旋结构。
活开气儿的下方需要设置搭接量。（ ）
A.工业企业的资金运动的程序可划分的基本环节有（ ）
B.“人命至重，有贵千金。”是唐代医家孙思邈所讲的。
C.下面哪些生活方式可以导致精气的过度消耗
D.烃类热裂解制乙烯工艺中加入水蒸气的主要作用是
在艺术创作中，偶然决定必然，必然在一定意义上决定偶然，偶然没有独立存在的价值。
A.学前儿童生长发育的不均衡性就是指他们生长发育速度的不均衡
B.()是我国的税制不统一在收入分配过程中的主要表现。
C.关于二维数据CSV存储问题，哪个选项的描述是错误的
D.非框架梁的编号是L（ ）
计算机系统的五大部件之间的互连方式有两种：____和____
A.“春蚕到死丝方尽”的下句是（ ）。
B.制度建设是团队管理中重要的一部分。（）
C.嵌入式Linux下，用户程序只能运行在 空间。
D.一般用微处理器的_____进行分类。
植物命名的双名法是指包括两部分（）
A.高跟鞋鞋跟高度在4-8CM为佳。
B.滴滴出行能满足人们哪些层次的需求
C.装配图上标注的尺寸数目是各零件图尺寸个数相加的结果。
D.关于十二指肠降部的毗邻，正确的说法包括哪些
一位推销员在推销一种试用
A.人生观是指人们对美好未来的向往和追求（ ）。
B.肽链延伸由许多循环组成，每加一个氨基酸就是一个循环，每个循环包括：
C.“款”和“识”形式有差别，款是凹面、识是凸面。
D.估计是对精算或估计过程中的近似计算。（ ）
智慧职教: 全自动磨边机的加工参数部分可中心仪上设置。
A.对于普通照片的描述，正确的是
B.谷雨是二十四节气的第( )个节气。
C.公元702年，武则天首创了武举制，更加促进了中原地区武术的发展。
D.王国维评文天祥词_______甚高，亦有境界，远在宋末诸词人之上。
晋朝出现的哪部作品是我国古代文学史上有名的情歌之一
A.绘图输入功能中都包含哪些内容（）
B.两个波源发出的波发生干涉现象的充分必要条件有：
C.李清照留存至今的词集是（ ）
D.英国的动画片《彼得兔》就是由绘本《彼得兔》改编而成
革命是解放生产力，改革也是解放生产力。
A.资本主义生产方式的基本矛盾是：
B.“金兰契互剖金兰语风雨夕闷制风雨词”一句中的“金兰”指的是哪两位女子的和解
C.找出划线部分读音与所给单词相同的一个。experience ( )
D.钢板墙板的工程量按设计图示尺寸以垂直投影面积计算
水体富营养化的基本成因是()。
A.脂肪大量动员时，肝内生成的乙酰CoA主要转变为下列哪种物质再向其他组织运输
B.《雅》的体裁与《国风》相比,不同之处在于()。
C.新生儿Apgar评分在多少分，考虑出现轻度窒息
D.关于混凝土的强度与无腹筋梁斜截面剪切破坏关系的描述，不正确的是。
肝硬变引起出血倾向和贫血的原因与下列哪项无关
A.南方受夏季风影响时间长，雨季长，降水多，河流汛期长。
B.下列哪种属食物中毒的范畴（ ）。
C._________适用于结构非弹性地震反应分析。
D.尿路感染的护理问题不包括
